Civitavecchia (Rome), Italy to Miami, Florida Cruise
Seabourn Sojourn by Seabourn Cruise Line
Europe34-night cruise departing November 15, 2026 from Civitavecchia (Rome), Italy
Arriving December 19, 2026 in Miami, Florida
Itinerary
- Day 1: Civitavecchia (Rome), Italy
- Day 2: Bonifacio, Corsica, France
- Day 3: Cagliari, Sardinia, Italy
- Day 4: Trapani, Italy
- Day 5: Valletta, Malta
- Day 6: La Goulette, Tunisia
- Day 7: Mahon, Minorca, Spain
- Day 8: Palma de Mallorca, Spain
- Day 9: Barcelona, Spain
- Day 10: Valencia, Spain
- Day 11: Cartagena, Spain
- Day 12: Malaga, Spain
- Day 13: Gibraltar, British Territory
- Day 14: Tangier, Morocco
- Day 15: Cadiz (Seville), Spain
- Day 16: Barca d'Alva, Portugal
- Day 17: Barca d'Alva, Portugal
- Day 18: Lisbon, Portugal
- Day 19: Funchal, Madeira, Portugal
- Day 20: Porto Santo, Portugal
- Day 21: Miami, Florida
Frequently Asked Questions
- How long is the Civitavecchia (Rome), Italy to Miami, Florida cruise?
- 34 nights on Seabourn Sojourn.
- What cruise line operates this route?
- Seabourn Cruise Line operates this cruise on the Seabourn Sojourn.
- What ports does this cruise visit?
- Civitavecchia (Rome), Italy, Bonifacio, Corsica, France, Cagliari, Sardinia, Italy, Trapani, Italy, Valletta, Malta, La Goulette, Tunisia, Mahon, Minorca, Spain, Palma de Mallorca, Spain, Barcelona, Spain, Valencia, Spain, Cartagena, Spain, Malaga, Spain, Gibraltar, British Territory, Tangier, Morocco, Cadiz (Seville), Spain, Barca d'Alva, Portugal, Barca d'Alva, Portugal, Lisbon, Portugal, Funchal, Madeira, Portugal, Porto Santo, Portugal, Miami, Florida
- When does this cruise depart?
- November 15, 2026
- Where does this cruise depart from?
- Civitavecchia (Rome), Italy